# Line slope calculator 8x-5y=-10

**Straight line given by points A[0; 2] and B[5; 10]**

## Calculation:

**Slope-intercept form of line:**y = 1.6x+2

**Canonical form of the line equation:**8x-5y+10 = 0

**Parametric form of the line equation:**

x = 5t

y = 8t+2 ; t ∈ R

**Slope:**m = 1.6

**Slope angle of line: φ =**57°59'41″ = 1.0122 rad

**X intercept:**x

_{0}= -1.25

**Y intercept:**y

_{0}= q = 2

**Distance line from the origin:**d

_{0}= 1.06

**The length of the segment AB: |AB| =**9.434

**Vector: AB =**(5; 8)

**Normal vector: n =**(8; -5)

**Midpoint of the segment AB: M =**[2.5; 6]

**Perpendicular Bisector equation:**5x+8y-60.5 = 0

**Vector OA = (0; 2) ; |OA| = 2**

**Vector OB = (5; 10) ; |OB| = 11.1803**

**Scalar product OA .OB = 20**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**